| twilit |
09-16-2012 05:56 AM |
Quote:
Posted by Blueh
(Post 198326)
Speaking of Math, this problem like fried my brain on my Hon. Algebra 2 test. Solve for C.
6AB+12AC-9BC=3ABC
This is why I like science better for the most part lol. Math is involved, but it sure isn't like the problem above for the most part.
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wow its been 4yrs since alg ii. If you were wanting a numeric value, there would have to be 3 equations, the 3 planes intersecting at one point. blablablah but since thats not the case, so you are probably looking to solve for "C" in terms of "A" and "B"... the best i can do is simply divide out 3AB:
C = 2 + (C/B) + (3C/A) hmm sorry cant seem to get C alone on left.
alg ii was just too much work, precalc was just a review of alg ii, but calculus is easy. ill go back to calculus class now.
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