In the hard coded AP script on graal v6, if a player kills another player with less than 30-20 AP, their AP is preserved because the other player is 'evil' by nature and it wouldn't effect their alignment. My question is: Is it the same case in Classic Iphone's alignment system?  

Posted by PerfectDark

In the hard coded AP script on graal v6, if a player kills another player with less than 30-20 AP, their AP is preserved because the other player is 'evil' by nature and it wouldn't effect their alignment. My question is: Is it the same case in Classic Iphone's alignment system?

no.

Besides this, does AP on Classic work the same as AP on iClassic?  

If you kill someone in the bottem two tiers it doesn't seem to effect ap.  

Posted by Pazx

If you want to kill people BEING A SAINT IS NOT FOR YOU.

This is obvious. I better make it bigger.

IF YOU WANT TO KILL PEOPLE, YOU WILL NOT BE A SAINT. YOU HAVE A CHOICE BETWEEN PKING AND HAVING A HIGH AP. Pick one.

You can spar without losing AP right? PKs also don't count in houses which was the whole point of my question. You're just having fun in your guild house right? What if your guild was doing an event that required killing in a house/guild house. Why lose AP for something like that? Now that brings me back to my original question that I don't need obvious answers for. Do you lose AP for killing other players in houses/guild houses?

EDIT: Found out myself. It does.  

Posted by Rufus

That was an answer, stop trying to have the best of both worlds.

Posted by GotenGraal

I'm not, once again it was a question.

Posted by GotenGraal

Quick questions lol. I still enjoy pking so would it be ok to pk on my non vip account and transfer to my main? I want my main account to be a saint. Would this mess up the AP and make me lose sainthood on my main?

???  

Posted by Talon

???

You didn't put his first comment. Can I ask a simple question and get an answer without the person being a smartass about it?  

Did we decide AP was not meant to be lowered when you win a spar?